Answer
Set E has a higher average and a larger spread
Work Step by Step
Dataset E: 113,183,479,120,117
Dataset F:145,129,153,135,142
Mean E: Add all the numbers and divide by 5 :$\frac{113+183+479+120+117}{5}$=202.4
Mean F: Add all the numbers and divide by 5: $\frac{145+129+153+135+142}{5}$=140.8
Dataset E has the larger average.
Range E: The difference between the largest and smallest number:479-113=366
Range F: The difference between the largest and smallest number:153-129=24
Dataset E has the larger spread.
Set E has a higher average and a larger spread since its mean and range is larger than F's.
