## Algebra 1: Common Core (15th Edition)

$x=4$ or $x=-1$
Given: $y=x^2-x-6$ $y=2x-2$ Substitute: $x^2-x-6=2x-2$ $x^2-3x-4=0$ $(x-4)(x+1)=0$ $x-4=0$ or $x+1=0$ $x=4$ or $x=-1$ The solutions of the system are $x=4$ and $x=-1$.