## Algebra 1: Common Core (15th Edition)

$A=n^2+4n+4$
The volume of the prism is: $V=Ah$ Substitute: $3n^3+13n^2+16n+4=A(3n+1)$ $A=\frac{3n^3+13n^2+16n+4}{3n+1}$ $n^2+4n+4$ ____________________________________ $3n+1) 3n^3+13n^2+16n+4$ $-3n^3-n^2$ ____________________________________ $12n^2+16n$ $-12n^2-4n$ ____________________________________ $12n+4$ $-12n-4$ ____________________________________ $0$ Hence, the answer is $A=n^2+4n+4$.