## Algebra 1: Common Core (15th Edition)

$\frac{1}{6}$
(x and y are in an inverse variation if xy=k) $\frac{1}{3}\times\frac{1}{4}=\frac{1}{12}$ so $x\times\frac{1}{2}=\frac{1}{12}$ $\frac{1}{2}x=\frac{1}{12}$ (Multiply each side by 2) $x=\frac{1}{6}$