Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 11 - Rational Expressions and Functions - 11-4 Adding and Subtracting Rational Expressions - Practice and Problem-Solving Exercises - Page 689: 54

Answer

$\frac{4c+11}{3c+1}$

Work Step by Step

Removing factors both in the numerator and the denominator: $\frac{\frac{7}{c+1}+4}{3-\frac{2}{c+1}}$ $=\frac{\frac{7+4(c+1)}{c+1}}{\frac{3(c+1)-2}{c+1}}$ $=\frac{7+4(c+1)}{c+1} \times \frac{c+1}{3(c+1)-2}$ $=\frac{4c+11}{3c+1}$
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