#### Answer

$\frac{1}{t+1}$

#### Work Step by Step

Given : $\frac{2t}{2t^{2}-t-3} - \frac{3}{2t^{2}-t-3}$
This becomes : $\frac{2t-3}{(t+1)(2t-3)}$
(Since they have the same denominator)
$= \frac{1}{t+1}$

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Published by
Prentice Hall

ISBN 10:
0133281140

ISBN 13:
978-0-13328-114-9

$\frac{1}{t+1}$

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