Answer
$\frac{9+21y^2}{21y^4}$
Work Step by Step
$\frac{3}{7y^4}+\frac{3}{3y^2}$
$=\frac{3.3}{7y^4.3}+\frac{3.7y^2}{3y^2.7y^2}$
$=\frac{9+21y^2}{21y^4}$
The solution is $\frac{9+21y^2}{21y^4}$.
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