The answer is $2m+3$.
Work Step by Step
Given: $(2m^2-m-3) \div (m+1)$ Begin the long division process: Divide: $2m^2 \div m =2m$ Multiply: $2m^2 +2m$ Then subtract: $-3m -3$ Repeat the process: Divide: $-3m \div m = -3$ Multiply: $-3(m+1)=-3m-3$ Then subtract. The remainder is $0$. The answer is $2m+3$.