## Algebra 1: Common Core (15th Edition)

$\frac{a^2+6a+5}{2a+2}=\frac{(a+5)(a+1)}{2(a+1)}=\frac{a+5}{2}$ $a$ cannot equal $-1$ Hence, $\frac{ab^3}{b^4} =\frac{a+5}{2}$ The statement is sometimes true, unless $a=-1$, where the equation is undefined.