Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 11 - Rational Expressions and Functions - 11-1 Simplifying Rational Expressions - Practice and Problem-Solving Exercises - Page 667: 9



Work Step by Step

The excluded values are x=0 because it makes the denominator zero. Reduce $\frac{4x^{3}}{28x^{4}}$ by dividing by $\frac{4}{4}$. $\frac{4x^{3}}{28x^{4}}$ $\div$ $\frac{4}{4}$ = $\frac{x^{3}}{7x^{4}}$. Subtract the powers of x. $\frac{x^{3}}{7x^{4}}$ = $\frac{1}{7x^{4-3}}$ = $\frac{1}{7x}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.