Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 10 - Radical Expressions and Equations - 10-6 Trigonometric Ratios - Got It? - Page 646: 1

Answer

$\sin E=\frac{4}{5}$ $\cos E=\frac{3}{4}$ $\tan E=\frac{4}{3}$

Work Step by Step

$\sin E=\frac{12}{15}=\frac{4}{5}$ $\cos E=\frac{9}{12}=\frac{3}{4}$ $\tan E=\frac{12}{9}=\frac{4}{3}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.