## Algebra 1: Common Core (15th Edition)

$\frac{\sqrt 3n}{n}$
Rationalize the denominator by multiplying the numerator and denominator by $\sqrt 2n$ $\frac{\sqrt 6}{\sqrt 2n}\times\frac{\sqrt 2n}{\sqrt 2n}$ Simplify $\frac{\sqrt 12n}{2n}$ $\frac{\sqrt 4\times\sqrt 3n}{2n}$ $\frac{2\sqrt 3n}{2n}$ $\frac{\sqrt 3n}{n}$