Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 10 - Radical Expressions and Equations - 10-1 The Pythagorean Theorem - Got It? - Page 616: 3

Answer

a. No, it is not a right triangle. b. Yes it is possible.

Work Step by Step

a. Let the side lengths be $a=20\; mm, b=47\; mm$ and $c=52\; mm$. We have $a^2+b^2=20^2+47^2=400+2209=2609$. and $c^2=52^2=2704$. It does not follow Pythagorean Theorem. Hence, this is not a right triangle. b. The given equation is $a^2+b^2=c^2$. Replace $a=2a,b=2b$ and $c=2c$ $(2a)^2+(2b)^2=(2c)^2$ Clear the parentheses $4a^2+4b^2=4c^2$ Divide the equation by $4$. $a^2+b^2=c^2$. This is a right triangle, because it follows Pythagorean theorem.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.