## Algebra 1: Common Core (15th Edition)

Published by Prentice Hall

# Chapter 1 - Foundations for Algebra - Chapter Review: 71

-100

#### Work Step by Step

We follow the instructions to plug in 5 for p: -$(2(5))^{2}$ Recall, because of order of operations, we multiply 2 and 5 first because the multiplication is in parenthesis. Thus, we find: $-(2(5))^{2} \\\\ =-(10)^{2} \\\\ =-100$

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