## Algebra 1: Common Core (15th Edition)

We follow the instructions to plug in 5 for p: -$(2(5))^{2}$ Recall, because of order of operations, we multiply 2 and 5 first because the multiplication is in parenthesis. Thus, we find: $-(2(5))^{2} \\\\ =-(10)^{2} \\\\ =-100$