Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 1 - Foundations for Algebra - 1-8 An Introduction to Equations - Got It? - Page 54: 3


$h =\frac{l}{14}$, where $h$ is the height, and $l$ is the length. Plug in $l$ as $49$ centimeters, and you will find that $h$ is $\frac{7}{2}$.

Work Step by Step

The question says that the length of the ball court is $14$ times the height of its wall. This means that the height is $\frac{1}{14}$ of the length. Convert this to an equation, where $l$ is the length and $h$ is the height. $h = \frac{1}{14}l$. If we plug in $l$ as $49$, then we find out that $h$ is $7/2$.
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