## Algebra 1: Common Core (15th Edition)

$h =\frac{l}{14}$, where $h$ is the height, and $l$ is the length. Plug in $l$ as $49$ centimeters, and you will find that $h$ is $\frac{7}{2}$.
The question says that the length of the ball court is $14$ times the height of its wall. This means that the height is $\frac{1}{14}$ of the length. Convert this to an equation, where $l$ is the length and $h$ is the height. $h = \frac{1}{14}l$. If we plug in $l$ as $49$, then we find out that $h$ is $7/2$.