Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 1 - Foundations for Algebra - 1-6 Multiplying and Dividing Real Numbers - Practice and Problem-Solving Exercises - Page 44: 69



Work Step by Step

We need the highest value of n to get a positive integer ending in 2 $(-n)^{3}$ To start off we need a number that has a cube ending in 2. Beetwen 0 and 9, 8 has 512 as its cube, which has 2 in the last place. $8^{3}$=512 If we replace n for 8, the result ends up being -512 because we multiply -8 three times. Multiplying two negative numbers gives us a positive number, but multiplying that number again with a negative one gives us a negative number. $(-(8))^{3}$=-512 That's why n has to be -8 instead of 8. $(-(-8))^{3}$=$8^{3}$=512
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