Answer
0
Work Step by Step
We start with ($7^{6}- 6^{5}) \times(8-8)$.
We see that 8-8 = 0, and any number that multiplies with 0 will be 0.
Therefore, we can write:
($7^{6}- 6^{5}) \times(8-8)=(7^{6}- 6^{5}) \times0 = 0$.
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 1 - Foundations for Algebra - 1-4 Properties of Real Numbers - Practice and Problem-Solving Exercises - Page 28: 51
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