## Algebra 1: Common Core (15th Edition)

We start with ($7^{6}- 6^{5}) \times(8-8)$. We see that 8-8 = 0, and any number that multiplies with 0 will be 0. Therefore, we can write: ($7^{6}- 6^{5}) \times(8-8)=(7^{6}- 6^{5}) \times0 = 0$.