Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 1 - Foundations for Algebra - 1-4 Properties of Real Numbers - Practice and Problem-Solving Exercises: 51

Answer

0

Work Step by Step

We start with ($7^{6}- 6^{5}) \times(8-8)$. We see that 8-8 = 0, and any number that multiplies with 0 will be 0. Therefore, we can write: ($7^{6}- 6^{5}) \times(8-8)=(7^{6}- 6^{5}) \times0 = 0$.
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