Discrete Mathematics and Its Applications, Seventh Edition

Published by McGraw-Hill Education
ISBN 10: 0073383090
ISBN 13: 978-0-07338-309-5

Chapter 6 - Section 6.4 - Binomial Coefficients and Identities - Exercises - Page 422: 31

Answer

According to corollary 2: $(_0^n)-(_1^n)+(_2^n)-...._-^+(_n^n) = 0$ On taking all negative terms to the RHS we get : $(_0^n)+(_2^n)+(_4^n).... = (_1^n)+(_3^n)+(_5^n)....$ Now in the equation above the LHS represents the number of subsets with even number of elements of a set containing n elements and the RHS denotes the number of subsets having odd number of elements. The above equation shows that both of them are equal. Hence it is proved that a nonempty set has the same number of subsets with an odd number of elements as it does subsets with an even number of elements

Work Step by Step

Same as above.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.