Discrete Mathematics and Its Applications, Seventh Edition

Published by McGraw-Hill Education
ISBN 10: 0073383090
ISBN 13: 978-0-07338-309-5

Chapter 2 - Section 2.4 - Sequences and Summations - Exercises - Page 169: 31

Answer

A. 1533 B. 510 C. 4923 D. 9842

Work Step by Step

A. This is a geometric progression with its initial value is 3 and ratio 2. Then, by the formula of geometric series, we can obtain that $3 + 3 * 2 + … + 3 * 2^{8} = 3 * \frac{2^{9} -1}{2-1} = 1533.$ B. By the formula of geometric series, $2 + 2^{2} + 2^{3} + … + 2^{8} = 2* \frac{2^{8}-1}{2-1} = 510.$ C. $(-3)^{2} + (-3)^{3} + (-3)^{4} +...+ (-3)^{8} = 9-27+81-243+729-2187+6561 = 4923.$ D. From answer C, we can obtain $\sum_{j=0}^{8} (-3)^{j} = 1 - 3 + 4923 = 4921$. Then, the result is $ 2 * 4923 = 9842. $
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