Answer
$ε_{T} = 0.348 $
Work Step by Step
Given:
true plastic strain of metal is 0.19
true stress- 500 MPa
value of k in Equation 6.19 - 825 MPa
Required:
true strain from application of 600 MPa
Solution:
Using Equation 6.19:
$n = \frac{ log σ_{T} - log K}{log ε_{T} } = \frac{log (500 MPa) - log (825 MPa)}{ log (0.19)} = 0.302$
Expressing $ε_{T}$ as an independent variable in Equation 16.9:
$ε_{T} = (\frac{σ_{T}}{K})^{1/n} = (\frac{600 MPa}{825 MPa})^{1/0.302} = 0.348 $
