Materials Science and Engineering: An Introduction

Published by Wiley
ISBN 10: 1118324579
ISBN 13: 978-1-11832-457-8

Chapter 4 - Imperfections in Solids - Questions and Problems - Page 136: 4.7c

Answer

Al=143 pm Zr=230 pm the atomic radius difference is much larger than 15 They do not satisfy the first condition so they are not completely soluble.

Work Step by Step

For a substitutional solid solution having complete solubility, the following conditions must be satisfied: 1. Atomic radius difference must be less than 15. 2. Both have same electronegativity. 3. Both have same crystal structure. 4.Both have same valence electrons. Al=143 pm Zr=230 pm the atomic radius difference is much larger than 15 They do not satisfy the first condition so they are not completely soluble.
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