Materials Science and Engineering: An Introduction

Published by Wiley
ISBN 10: 1118324579
ISBN 13: 978-1-11832-457-8

Chapter 3 - The Structure of Crystalline Solids - Questions and Problems - Page 98: 3.12b



Work Step by Step

Given the atomic weight=47.87g\mol, $\rho=4.51$, and r=$\frac{a}{2}$ for HCP: $V_{c}=6r^2c\sqrt{3}$ where $\frac{c}{a}=1.58$ $V_{c}=6\times3.266{\sqrt{3}}r^3$ $a=(\frac{V_{c}}{4.105})^{\frac{1}{3}}$=0.296nm $c=1.58\times0.296=0.468nm$
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