Materials Science and Engineering: An Introduction

Published by Wiley
ISBN 10: 1118324579
ISBN 13: 978-1-11832-457-8

Chapter 3 - The Structure of Crystalline Solids - Questions and Problems - Page 97: 3.5


APF of BCC is 0.68

Work Step by Step

$APF={\text{volume of atomic unit cell}}/{\text{total unit cell volume}}$ $V_{s}=\frac{4}{3}\pi r^3$ As we know BCC has a total of 2 atoms: $V_{s}=2\times\frac{4}{3}\pi r^3=\frac{8}{3}\pi r^3$ Thus: $V_{c}=a^3={\frac{4}{\sqrt{3}}r}^3$ $V_{c}=\frac{64}{3\sqrt{3}}r^3$ APF =$\frac{\frac{8}{3}\pi r^3}{\frac{64}{3\sqrt{3}}r^3}=0.68$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.