Materials Science and Engineering: An Introduction

Published by Wiley
ISBN 10: 1118324579
ISBN 13: 978-1-11832-457-8

Chapter 21 - Optical Properties - Questions and Problems - Page 866: 21.1

Answer

$\nu = 6*10^{14}$ Hz $E = 3.98*10^{-19}$ J

Work Step by Step

Given: $\lambda = 5*10^{-7}$ m $c = \lambda \nu$ $\nu = c/\lambda$ where $c = 3*10^8$ m/s $E = h\nu$ where $h = 6.626*10^{-34}$ J*s Thus: $\nu = 6*10^{14}$ Hz $E = 3.98*10^{-19}$ J
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.

GradeSaver will pay $15 for your literature essays
GradeSaver will pay $25 for your college application essays
GradeSaver will pay $50 for your graduate school essays – Law, Business, or Medical
GradeSaver will pay $10 for your Community Note contributions
GradeSaver will pay $500 for your Textbook Answer contributions