## Materials Science and Engineering: An Introduction

$μ = 1.26 \times 10^{-6} H/m$
Given: magnetic flux density (B)= 0.630 tesla $H _{field }= 5 \times 10^{5} A/m$ Required: magnetic permeability (μ) Solution: Using Equation 20.2: $μ = \frac{B}{H} = \frac{0.630 tesla}{5 \times 10^{5} A/m} = 1.26 \times 10^{-6} H/m$