Materials Science and Engineering: An Introduction

Published by Wiley
ISBN 10: 1118324579
ISBN 13: 978-1-11832-457-8

Chapter 18 - Electrical Properties - Questions and Problems - Page 780: 18.30b


$σ = 16,000 (Ω-m)^{-1} $

Work Step by Step

Given: Germanium to which $ 10 ^{24} m^{-3}$ As atoms have been added is an extrinsic semiconductor at room temperature, and virtually all the As atoms may be thought of as being ionized (i.e., one charge carrier exists for each As atom). Required: electrical conductivity of this material, assuming electron and hole mobilities of 0.1 and 0.05 $m^{2}/V-s$, respectively Solution: The material is n-type extrinsic; thus, Equation 18.16 is applicable using $n = 10 ^{24} m^{-3}$: $σ = n|e|μ_{e} = (10 ^{24} m^{-3})(1.6 \times 10^{-19} C)( 0.1 m^{2}/V-s)= 16,000 (Ω-m)^{-1} $
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