Answer
$M_{n} = 6.31 \times 10^{5} g/mol$
Work Step by Step
Given:
For polypropylene, $m= 42.08 g/mol$.
Required:
The number-average molecular weight for a polypropylene for which the degree of polymerization is 15,000.
Solution:
Using Equation 14.6:
$M_{n} = (DP)(m) = (15,000)(42.08 g/mol) = 6.31 \times 10^{5} g/mol$
