Answer
By observing the shown mannometere , connected to the storage tank by a line filled with gas, we have $P_{a} = P_{gas}$ and $P_{a} = P_{b}$ .
Now,
$P_{gas}$ = $P_{atm}$ $+$ $\rho$gL
$ $ => 101 Kpa + (13.59 $g/$$cm^{3}$) ( 1 kg/ $10^{3}$g )($ 10^{2}$ cm/1 m)^3 ( 9.81 $\frac{m}{s^{2}}$)( 1 m ) ($\frac{1 N}{1 Kg.m/s^{2}} $) ($\frac{1 KPa}{1 N/m^{2}} $)
= 101 Kpa +133.3 Kpa
= 234.3 Kpa
Work Step by Step
By observing the shown mannometere , connected to the storage tank by a line filled with gas, we have $P_{a}$ = $P_{gas}$ and $P_{a}$ = $P_{b}$ .
Now,
$P_{gas}$ = $P_{atm}$ $+$ $\rho$gL
$ $ => 101 Kpa + (13.59 $g/$$cm^{3}$) ( 1 kg/ $10^{3}$g )($ 10^{2}$ cm/1 m)^3 ( 9.81 $\frac{m}{s^{2}}$)( 1 m ) ($\frac{1 N}{1 Kg.m/s^{2}} $) ($\frac{1 KPa}{1 N/m^{2}} $)
= 101 Kpa +133.3 Kpa
= 234.3 Kpa
