Fundamentals of Engineering Thermodynamics 8th Edition

Published by Wiley
ISBN 10: 1118412931
ISBN 13: 978-1-11841-293-0

Chapter 1 - Problems: Developing Engineering Skills - Page 30: 1.7

Answer

(a) $F_{gravitation}$ = mg therefore, g=$F_{gravitation}$/m = (144.4 lbf/150 lb)$\times$(32.174 lb.ft/($s^{2}$$\times$ 1 lbf ) )= 30.97 ft/$s^{2}$. (b) Mass value remains the same. So $F_{gravitation}$ = (150 lb)( 32.174 ft/$s^{2}$)( 1 lbf/ 32.174 lb.ft/$s^{2}$ ) = 150 lbf.

Work Step by Step

(a) $F_{gravitation}$ = mg therefore, g=$F_{gravitation}$/m = (144.4 lbf/150 lb)$\times$(32.174 lb.ft/($s^{2}$$\times$ 1 lbf ) )= 30.97 ft/$s^{2}$. (b) Mass value remains the same. So $F_{gravitation}$ = (150 lb)( 32.174 ft/$s^{2}$)( 1 lbf/ 32.174 lb.ft/$s^{2}$ ) = 150 lbf.
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