## Fundamentals of Engineering Thermodynamics 8th Edition

Published by Wiley

# Chapter 1 - Checking Understanding - Page 28: 12

#### Answer

Specific volume = $m^{3}$/kg (mass basis) Specific volume = $m^{3}$/ kmol (molar basis)

#### Work Step by Step

Specific volume = $m^{3}$/kg (mass basis) Specific volume = $m^{3}$/ kmol (molar basis)

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