Shigley's Mechanical Engineering Design 10th Edition

Published by McGraw-Hill Education
ISBN 10: 0073398209
ISBN 13: 978-0-07339-820-4

Chapter 14 - Problems - Page 772: 14-3

Answer

Bending Stress = 68.6 MPa

Work Step by Step

Pitch Diameter, $d=N * m$ = 18 * 1.25 = 22.5 mm where, N = number of teeth m= module Lewis form factor, $Y=0.309$ ; for 18 teeth with 20degree pressure angle Pitch line velocity, $V=( pi ∗ d ∗ n)/60$ ; where; n = speed in rpm therefore $V = ( 3.14 * 22.5 * 0.001 * 1800 )/60 = 2.121 m/s$ Velocity Factor, $K=(6.1+V)/6.1$ ; for cut or milled profile therefore $K = (6.1+2.121)/6.1= 1.348$ Tangential load, $W=(60000∗h)/( pi * d * n )$ ; where h is power in kW therefore $W=(60000∗0.5)/( 3.14 * 22.5 * 1800 ) = 0.2358 kN = 235.8 N$ $BendingStress=(K∗W)/(F ∗ m * Y)$ ; where F is facewidth $Bending Stress =( 1.348 * 235.8 )/( 12 * 1.25 * 0.309)$ $Bending Stress = 68.6 MPa$
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