Shigley's Mechanical Engineering Design 10th Edition

Published by McGraw-Hill Education
ISBN 10: 0073398209
ISBN 13: 978-0-07339-820-4

Chapter 14 - Problems - Page 772: 14-2

Answer

Bending Stress = 9.34 kpsi

Work Step by Step

Pitch Diameter, $d=N/P$ = 18/10 = 1.8 inches where, N = number of teeth P = diametral pitch Lewis form factor, $Y=0.309$ ; for 18 teeth with 20degree pressure angle Pitch line velocity, $V=(pi ∗ d ∗ n)/12$ ; where; n = speed in rpm therefore V = ( 3.14 * 1.8 * 600 )/12 = 282.7 ft/min Velocity Factor, $K=(1200+V)/1200$ ; for cut or milled profile therefore K = (1200+282.7)/1200 = 1.236 Tangential load, $W=(33000∗hp)/V$ ; where hp is horse power therefore W = (33000 * 2 )/ 282.7 = 233.5 lbf $BendingStress=(K∗W∗P)/(F∗Y)$ ; where F is facewidth Bending Stress = ( 1.236 * 233.5 * 10 ) / ( 1* 0.309 ) = 9340 psi Bending Stress = 9.34 kpsi
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.