Answer
$209.2\text{ kPa}$
Work Step by Step
$P_{gauge}=\rho\cdot g\cdot h=1000\cdot 9.81\cdot 11=107910\text{ Pa}$
$P_{atm}\approx 101325\text{ Pa}$
$P_{abs}=P_{gauge}+P_{atm}=107910+101325=209235\text{ Pa}\approx 209.2\text{ kPa}$
Munson, Young and Okiishi's Fundamentals of Fluid Mechanics, Binder Ready Version 8th Edition
by Gerhart, Philip M.; Gerhart, Andrew L.; Hochstein, John I.
Published by
Wiley
ISBN 10:
1119080703
ISBN 13:
978-1-11908-070-1
Chapter 2 - Problems - Page 81: 2.4
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
