# Chapter 1 - Problems - Page 31: 1.2

The Mach number, Ma, is dimensionless.

#### Work Step by Step

For an airplane flying at velocity V in air at absolute temperature T, the Mach number is: $Ma=\frac{V}{\sqrt kRT}$ Where (Using the International System of Units), $V=\frac{m}{s}=LT^{-1}$ $K=dimensionless$ (Given) $R=\frac{J}{KgK}=\frac{Nm}{KgK}=\frac{Kgm^{2}}{s^{2}KgK}=\frac{m^{2}}{s^{2}K}=L^{2}T^{-2} Θ^{-1}$ $T=K= Θ$ Therefore, $Ma=LT^{-1}(L^{2}T^{-2}Θ^{-1}\timesΘ)^{-1/2}=LT^{-1}(L^{2}T^{-2}Θ^{0})^{-1/2}=LT^{-1}(LT^{-1}Θ^{0})^{-1}$ $Ma=L^{0}T^{0}Θ^{0}$ Thus, it's proven that the Mach number, Ma, is dimensionless.

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.