Engineering Mechanics: Statics & Dynamics (14th Edition)

Published by Pearson
ISBN 10: 0133915425
ISBN 13: 978-0-13391-542-6

Chapter 8 - Friction - Section 8.8 - Rolling Resistance - Problems - Page 454: 108



Work Step by Step

We know that $M=\frac{2}{3}\mu P(\frac{R_2^3-R_1^3}{R_2^2-R_1^2})$ This can be rearranged as: $\mu=\frac{M}{\frac{2}{3}P(\frac{R_2^3-R_1^3}{R_2^2-R_1^2})}$ We plug in the known values to obtain: $\mu=\frac{200}{\frac{2}{3}(8000)[\frac{(0.100)^3-(0.075)^3}{(0.100)^2-(0.075)^2}]}$ This simplifies to: $\mu=0.284$
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