Engineering Mechanics: Statics & Dynamics (14th Edition)

Published by Pearson
ISBN 10: 0133915425
ISBN 13: 978-0-13391-542-6

Chapter 8 - Friction - Section 8.2 - Problems Involving Dry Friction - Problems - Page 421: 19



Work Step by Step

We know that $F_B=\mu_s N_B$ $\implies F_B=0.35N_B$ We also know that $\Sigma M_B=0$ $\implies N_A(3)-P(3-1)=0$ $\implies N_A(3)-P(2)=0$ This simplifies to: $N_A=200lb$
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