Engineering Mechanics: Statics & Dynamics (14th Edition)

Published by Pearson
ISBN 10: 0133915425
ISBN 13: 978-0-13391-542-6

Chapter 8 - Friction - Section 8.2 - Problems Involving Dry Friction - Preliminary Problems - Page 415: 2

Answer

$10~N\cdot m$

Work Step by Step

We know that $f_A=\mu_s N_A$ We plug in the known values to obtain: $f_A=0.1\times 100N=10N$ As moment at point O is $0$ $\implies \Sigma M_{\circ}=0$ $\implies M=f_A(1)$ $\implies M=10(1)=10~N\cdot m$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.