Answer
$\begin{aligned} & F_{K J}=11.25 \mathrm{kip}(\mathrm{T}) \\ & F_{C D}=9.375 \mathrm{kip}(\mathrm{C}) \\ & F_{C J}=3.125 \mathrm{kip}(\mathrm{C}) \\ & F_{D J}=0\end{aligned}$
Work Step by Step
$
\begin{array}{ll}
↺+\Sigma M_C=0 ; & -9500(18)+4000(9)+F_{K J}(12)=0 \\
& F_{K J}=11250 \mathrm{lb}=11.2 \mathrm{kip}(\mathrm{T}) \\
↺+\Sigma M_J=0 ; & -9500(27)+4000(18)+8000(9)+F_{C D}(12) \\
& F_{C D}=9375 \mathrm{lb}=9.38 \mathrm{kip}(\mathrm{C}) \\
\rightarrow \Sigma F_x=0 ; & -9375+11250-\frac{3}{5} F_{C J}=0 \\
& F_{C J}=3125 \mathrm{lb}=3.12 \mathrm{kip}(\mathrm{C}) \\
\text { Joint } D: & F_{D J}=0
\end{array}
$
