Engineering Mechanics: Statics & Dynamics (14th Edition)

Published by Pearson
ISBN 10: 0133915425
ISBN 13: 978-0-13391-542-6

Chapter 6 - Structural Analysis - Section 6.4 - The Method of Sections - Problems - Page 298: 30

Answer

$\begin{aligned} & F_{C D}=3375 \mathrm{lb}(\mathrm{C}) \\ & F_{H I}=6750 \mathrm{lb}(\mathrm{T}) \\ & F_{C H}=5625 \mathrm{lb}(\mathrm{C})\end{aligned}$

Work Step by Step

$\begin{array}{ll}↺+\Sigma M_H=0 ; & F_{C D}(4)-1500(6)-1500(3)=0 \\ & F_{C D}=3375 \mathrm{lb}(\mathrm{C}) \\ ↺+\Sigma M c=0 ; & F_{H I}(4)-1500(3)-1500(6)-1500(9)=0 \\ & F_{H I}=6750 \mathrm{lb}(\mathrm{T}) \\ +\uparrow \Sigma F_y=0 ; & F_{C H}\left(\frac{4}{5}\right)-1500-1500=0 \\ & F_{C H}=5625 \mathrm{lb}(\mathrm{C})\end{array}$
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