Chapter 4 - Force System Resultants - Section 4.9 - Reduction of a Simple Distributed Loaded - Problems - Page 198: 150

$$ \begin{aligned} & F_R=51.0 \mathrm{kN} \downarrow \\ & M_{R_o}=914 \mathrm{kN} \cdot \mathrm{m} \end{aligned} $$

$$ \begin{aligned} & +\uparrow F_R=\Sigma F_y ; \quad F_R=-22.5-13.5-15.0 \\ & =-51.0 \mathrm{kN}=51.0 \mathrm{kN} \downarrow \\ & ↺+M_{R_a}=\Sigma M_o ; \quad M_{R_a}=-500-22.5(5)-13.5(9)-15(12) \\ & =-914 \mathrm{kN} \cdot \mathrm{m} \\ & =914 \mathrm{kN} \cdot \mathrm{m}(\text { Clockwise }) \\ & \end{aligned} $$