Answer
$\begin{aligned} & F_R=197 \mathrm{lb} \\ & \theta=42.6^{\circ} \mathrm{} \\ & d=5.24 \mathrm{ft}\end{aligned}$
Work Step by Step
$
\begin{aligned}
& \rightarrow F_{R x}=\Sigma F_x ; \quad F_{R x}=150\left(\frac{4}{5}\right)+50 \sin 30^{\circ}=145 \mathrm{lb} \\
& +\uparrow F_{R y}=\Sigma F_y ; \quad F_{R y}=50 \cos 30^{\circ}+150\left(\frac{3}{5}\right)=133.3 \mathrm{lb} \\
& F_R=\sqrt{(145)^2+(133.3)^2}=197 \mathrm{lb} \\
& \theta=\tan ^{-1}\left(\frac{133.3}{145}\right)=42.6^{\circ} \\
& ↺+M_{R A}=\Sigma M_A ; \quad 145 d\\&=150\left(\frac{4}{5}\right)(2)-50 \cos 30^{\circ}(3)+50 \sin 30^{\circ}(6)+500 \\
& d=5.24 \mathrm{ft}
\end{aligned}
$
