Answer
$$
\begin{aligned}
& F_R=10.75 \mathrm{kip} \downarrow \\
& d=9.26 \mathrm{ft}
\end{aligned}
$$
Work Step by Step
Equivalent Force:
$$
\begin{aligned}
+\uparrow F_R=\Sigma F_y ; \quad F_R & =-1750-5500-3500 \\
& =-10750 \mathrm{lb}=10.75 \mathrm{kip} \downarrow
\end{aligned}
$$
Location of Resultant Force From Point A:
$$
\begin{array}{rr}
↺+M_{R_A}=\Sigma M_A ; \quad 10750(d) & =3500(20)+5500(6)-1750(2) \\
d & =9.26 \mathrm{ft}
\end{array}
$$
