Answer
$$
\begin{aligned}
& \mathbf{F}_R=\{-40 \mathbf{j}-40 \mathbf{k}\} \mathbf{N} \\
& \mathbf{M}_{R A}=\{-12 \mathbf{j}+12 \mathbf{k}\} \mathrm{N} \cdot \mathrm{m}
\end{aligned}
$$
Work Step by Step
$$
\begin{aligned}
\mathbf{F}_R & =\mathbf{F}_1+\mathbf{F}_2 \\
\mathbf{F}_R & =\{-40 \mathbf{j}-40 \mathbf{k}\} \mathbf{N} \\
\mathbf{M}_{R A} & =\Sigma(\mathbf{r} \times \mathbf{F}) \\
& =\left|\begin{array}{ccc}
\mathbf{i} & \mathbf{j} & \mathbf{k} \\
-0.3 & 0 & 0.08 \\
0 & -40 & 0
\end{array}\right|+\left|\begin{array}{ccc}
\mathbf{i} & \mathbf{j} & \mathbf{k} \\
-0.3 & 0.08 & 0 \\
0 & 0 & -40
\end{array}\right| \\
\mathbf{M}_{R A} & =\{-12 \mathbf{j}+12 \mathbf{k}\} \mathbf{N} \cdot \mathrm{m}
\end{aligned}
$$
