Engineering Mechanics: Statics & Dynamics (14th Edition)

Published by Pearson
ISBN 10: 0133915425
ISBN 13: 978-0-13391-542-6

Chapter 4 - Force System Resultants - Section 4.7 - Simplification of a Force and Couple System - Problems - Page 175: 107

Answer

$$ \begin{aligned} & \mathbf{F}_R=\{270 \mathbf{k}\} \mathbf{N} \\ & \mathbf{M}_{R O}=\{-2.22 \mathbf{i}\} \mathrm{N} \cdot \mathrm{m} \end{aligned} $$

Work Step by Step

$$ \begin{array}{ll} \mathbf{F}_R=\Sigma \mathbf{F}_z ; & \mathbf{F}_R=\{2(35+45+23+32) \mathbf{k}\}=\{270 \mathbf{k}\} \mathbf{N} \\ \mathbf{M}_{R O_x}=\Sigma \mathbf{M}_{O_x} ; & \mathbf{M}_{R O}=[-2(35)(0.075)+2(32)(0.015)\\&+2(23)(0.045)] \mathbf{i} \\ & \mathbf{M}_{R O}=\{-2.22 \mathbf{i}\} \mathbf{N} \cdot \mathrm{m} \end{array} $$
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