Answer
$$
\begin{aligned}
& M_2=424 \mathrm{~N} \cdot \mathrm{m} \\
& M_3=300 \mathrm{~N} \cdot \mathrm{m}
\end{aligned}
$$
Work Step by Step
$$
\begin{array}{ll}
\left(M_R\right)_y=\Sigma M_y ; & 0=M_2 \sin 45^{\circ}-300 \\
& M_2=424.26 \mathrm{~N} \cdot \mathrm{m}=424 \mathrm{~N} \cdot \mathrm{m} \\
\left(M_R\right)_x=\Sigma M_x ; & 0=424.26 \cos 45^{\circ}-M_3 \\
& M_3=300 \mathrm{~N} \cdot \mathrm{m}
\end{array}
$$
