Engineering Mechanics: Statics & Dynamics (14th Edition)

Published by Pearson
ISBN 10: 0133915425
ISBN 13: 978-0-13391-542-6

Chapter 4 - Force System Resultants - Section 4.6 - Moment of a Couple - Problems - Page 163: 82

Answer

$$ \mathbf{M}_C=78.1 \mathrm{lb} \cdot \mathrm{ft} $$

Work Step by Step

$$ \begin{aligned} \mathbf{r}_{C B} & =\{-3 \mathbf{i}-2.5 \mathbf{j}\} \mathrm{ft} \\ \mathbf{M}_C & =\mathbf{r}_{C B} \times \mathbf{F} \\ & =\left|\begin{array}{ccc} \mathbf{i} & \mathbf{j} & \mathbf{k} \\ -3 & -2.5 & 0 \\ 0 & 0 & 20 \end{array}\right| \\\\ \mathbf{M}_C & =\{-50 \mathbf{i}+60 \mathbf{j}\} \mathrm{lb} \cdot \mathrm{ft} \\ M_C & =\sqrt{(-50)^2+(60)^2}=78.1 \mathrm{lb} \cdot \mathrm{ft} \end{aligned} $$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.