Engineering Mechanics: Statics & Dynamics (14th Edition)

Published by Pearson
ISBN 10: 0133915425
ISBN 13: 978-0-13391-542-6

Chapter 4 - Force System Resultants - Section 4.6 - Moment of a Couple - Problems - Page 161: 70

Answer

$$ \left.\left(M_R\right)_C=435 \mathrm{lb} \cdot \mathrm{ft}\right) $$

Work Step by Step

$$ \begin{aligned} \mathrm{↺}+\left(M_R\right)_{\mathrm{C}} & =200(1.5)+125 \cos 30^{\circ}(1.25) \\ & =435.32 \mathrm{lb} \cdot \mathrm{ft}=435 \mathrm{lb} \cdot \mathrm{ft}↺ \end{aligned} $$
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