Engineering Mechanics: Statics & Dynamics (14th Edition)

Published by Pearson
ISBN 10: 0133915425
ISBN 13: 978-0-13391-542-6

Chapter 4 - Force System Resultants - Section 4.5 - Moment of a Force about a Specified Axis - Problems - Page 153: 61

Answer

$$M_{A B}=136 \mathrm{~N} \cdot \mathrm{m} $$

Work Step by Step

$$ \begin{aligned} & \mathbf{u}_{A B}=\frac{\{3.5 \mathbf{i}+0.5 \mathbf{j}\}}{\sqrt{(3.5)^2+(0.5)^2}} \\ & \mathbf{u}_{A B}=\{0.9899 \mathbf{i}+0.1414 \mathbf{j}\} \\ & M_{A B}=\mathbf{u}_{A B} \cdot\left(\mathbf{r}_{A D} \times \mathbf{F}\right)=\left|\begin{array}{ccc} 0.9899 & 0.1414 & 0 \\ 2.5 & 0 & 4 \\ 50 & -20 & -80 \end{array}\right| \\ & M_{A B}=136 \mathrm{~N} \cdot \mathrm{m} \end{aligned} $$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.