Answer
No
Yes
Work Step by Step
$$
M_x=30\left(\sqrt{(0.5)^2-(0.3)^2}\right)=12 \mathrm{~N} \cdot \mathrm{m}<14 \mathrm{~N} \cdot \mathrm{m}, \quad \text { No }
$$
For $\left(M_x\right)_{\max }$, apply force perpendicular to the handle and the $x$-axis.
$$
\left(M_s\right)_{\max }=30(0.5)=15 \mathrm{~N} \cdot \mathrm{m}>14 \mathrm{~N} \cdot \mathrm{m}, \quad \text { Yes }
$$
