Answer
$F=239 \mathrm{lb}$
Work Step by Step
$\begin{aligned} M_P & =F \cos 30^{\circ}(43)+F \sin 30^{\circ}(6) \quad \text { Set } M_P=800(12) \mathrm{lb} \cdot \text { in. } \\ 800(12) & =F \cos 30^{\circ}(43)+F \sin 30^{\circ}(6) \\ F & =239 \mathrm{lb}\end{aligned}$
